Y = − ( x − 2) 2 4 y = ( x 2) 2 4 Use the vertex form, y = a ( x − h) 2 k y = a ( x h) 2 k, to determine the values of a a, h h, and k k a = − 1 a = 1 h = 2 h = 2 k = 4 k = 4 Since the value of a a is negative, the parabola opens down Opens Down Find the vertex ( h, k) ( h, k) If P(x1, y1) and Q(x2, y2) are two points on the parabola y^2 = 8ax, at which the normal meets in (18, 12), then the length of the chord PQ is asked in Mathematics by RiteshBharti (539k points) parabola;Answer (1 of 4) Distance between two points (x1,y1),(x2,y2) is \sqrt{(x1^2x2^2)(y1^2y2^2)} So we have to find here (x1x2)^2 and (y1y2)^2 "Actually Points ((x1,y1) and (x2,y2) are the solution of the Given equation of Parabola and equation of Line when solved Simultaneously" So For fi 9 1 Quadratic Graphs Quadratic Function A Function Y=4-x^2 parabola